[2z-(11z+2)]=2+(6z+6)

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Solution for [2z-(11z+2)]=2+(6z+6) equation:


Simplifying
[2z + -1(11z + 2)] = 2 + (6z + 6)

Reorder the terms:
[2z + -1(2 + 11z)] = 2 + (6z + 6)
[2z + (2 * -1 + 11z * -1)] = 2 + (6z + 6)
[2z + (-2 + -11z)] = 2 + (6z + 6)

Reorder the terms:
[-2 + 2z + -11z] = 2 + (6z + 6)

Combine like terms: 2z + -11z = -9z
[-2 + -9z] = 2 + (6z + 6)

Remove brackets around [-2 + -9z]
-2 + -9z = 2 + (6z + 6)

Reorder the terms:
-2 + -9z = 2 + (6 + 6z)

Remove parenthesis around (6 + 6z)
-2 + -9z = 2 + 6 + 6z

Combine like terms: 2 + 6 = 8
-2 + -9z = 8 + 6z

Solving
-2 + -9z = 8 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-2 + -9z + -6z = 8 + 6z + -6z

Combine like terms: -9z + -6z = -15z
-2 + -15z = 8 + 6z + -6z

Combine like terms: 6z + -6z = 0
-2 + -15z = 8 + 0
-2 + -15z = 8

Add '2' to each side of the equation.
-2 + 2 + -15z = 8 + 2

Combine like terms: -2 + 2 = 0
0 + -15z = 8 + 2
-15z = 8 + 2

Combine like terms: 8 + 2 = 10
-15z = 10

Divide each side by '-15'.
z = -0.6666666667

Simplifying
z = -0.6666666667

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